Q.1. Least positive integral value of x satisfying the inequality $\log_{x} (x^{2} + 4) > 2$ is
(1) 2
(2) 3
(3) 4
(4) 5

Open in App

Solution

$Hi, \log_{x} (x^{2} + 4) > 2 so x^{2} + 4 > x^{2} so here least positive value from options is 2$

Suggest Corrections

Similar questions

x

\frac{(2 - x^{2})^{3} (x - 3)^{5}}{(x + 1) (x^{2} - 3 x - 4)} \geq 0

x

\frac{(2 - x^{2})^{3} (x - 3)^{5}}{(x + 1) (x^{2} - 3 x - 4)} \geq 0

x

\frac{x^{2} - 3 x + 4}{x^{2} - 6 x + 8} \leq 0

x

^{10} C_{x - 1} > 2 \cdot^{10} C_{x}

f : R \to R, f (x) = 1 - x - 4 x^{3},

x \in [0, 4]

4 f^{3} (x) + f (1 - 2 x) + f (x) < 1

Join BYJU'S Learning Program