Q.10. A 1 $μ$ F capacitor is connected to a 220 V - 50 Hz a.c. source. Find the virtual value of current through circuit. Find the virtual value of current through circuit. What is the peak value of voltage across the capacitor?

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Solution

Dear student,
$X_{c} = \frac{1}{2 π f C}$
$X_{c} = \frac{1}{2 \times 3.14 \times 50 \times 1 \times 10^{- 6}} X_{c} = 3180 o h m s I_{r m s} = \frac{E}{X_{c}} = \frac{220}{3180} = 0.069 A P e a k c u r r e n t = \sqrt{2} \times I_{r m s} P e a k c u r r e n t = 1.41 \times 0.069 P e a k c u r r e n t = 0.097 A$

$P e a k v o l t a g e = 0.097 \times 3180 P e a k v o l t a g e = 310.2 V$

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