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Question

Q.10. Find the vector equation of the plane passing through the points (1, 1, 1), (1, - 1, 1) and (- 7, - 3, - 5).

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Solution

Dear student
Let the points be A(1,1,1), B(1,-1,1),C(-7,-3-,5)The required plane passes through the point A(1,1,1) whose position vector is a=i^+j^+k^ and is normal to the vector n given byn=AB×ACWe have,AB=i^-j^+k^-(i^+j^+k^)=-2j^and AC=(-7i^-3j^-5k^)-(i^+j^+k^)=-8i^-j^-6k^n=AB×AC=i^j^k^0-20-8-1-6=i^12-j^(0)+k^(-16)=12i^-16k^The vector equation of the required plane is r.n=a.nr.12i^-16k^=(i^+j^+k^).(12i^-16k^)r.12i^-16k^=12-16r.(3i^-4j^)+1=0
Regards

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