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Question

Q.10. The sum of three prime numbers is 100. If one of them exceeds the other by 36, then largest number is
(1) 73
(2) 91
(3) 67
(4) 57

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Solution

Dear student

Let x , x + 36 and y are the three prime numbers. According to the given condition, x + x +36 + y = 100 2x + y = 64 ..................(1) Since x is a prime number, then 2x will be an even number. Also addition of two even numbers results in an even number, from equation (1),we can conclude that y must be an even prime number. y = 2 , as " 2 " is the only even prime number. Put y = 2 in equation (1), we get 2x + 2 = 64 x = 31 So the required prime numbers are 31, 31+36, 2 or 31, 67 and 2
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