Q.12. Find three consecutive numbers such that the sum of the second and third exceeds the first by 14.

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Solution

Dear Student,

$L e t t h e t h r e e c o n s e c u t i v e n u m b e r s b e x, x + 1 a n d x + 2 G i v e n, (x + 1) + (x + 2) = x + 14 2 x + 3 = x + 14 2 x - x = 14 - 3 x = 11 T h e t h r e e c o n s e c u t i v e n u m b e r s a r e 11, 12 a n d 13 .$

Regards

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Q.12. Find three consecutive numbers such that the sum of the second and third exceeds the first by 14.

Dear Student, Let the three consecutive numbers be x,x+1 and x+2Given, x+1+x+2 = x+142x+3 = x+142x-x = 14-3x = 11The three consecutive numbers are 11,12 and 13. Regards

Dear Student,

$L e t t h e t h r e e c o n s e c u t i v e n u m b e r s b e x, x + 1 a n d x + 2 G i v e n, (x + 1) + (x + 2) = x + 14 2 x + 3 = x + 14 2 x - x = 14 - 3 x = 11 T h e t h r e e c o n s e c u t i v e n u m b e r s a r e 11, 12 a n d 13 .$

Regards