wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Q. 15 & 7 (system of particles, Normal Reaction, work Energy Theorem)
1. A ball of mass m and radius r is released from rest inside a hollow smooth sphere of mass m and radius R as shown in figure. The horizontal surface is smooth. The normal reaction on the ball when it reaches the lowest position is (r << R)
1168287_485ef326e9c74627a08feaf1226f248b.PNG

A
2 mg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3 mg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4 mg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5 mg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3 mg
R.E.F image
Solution
From AB,Wgravity=mgR
so by work - Energy Theorem,
wnet= KE
Here, mgR=mv22m(0)22
2mg=mv2R
Also, N-mg = ma [second law of motion]
Here a centripetal aun=v2R
N=mv2R+mg=2mg+mg=3mg
Option - B is correct

1147339_1168287_ans_79125054b7e04104893f8f21f6370090.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Losing Weight Using Physics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon