Q.184. A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature T. Neglecting all vibrational modes, the total internal energy of the system is
(1) 4 RT
(2) 15 RT
(3) 9 RT
(4) 11 RT

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Solution

$2 m o l e s o f o x y g e n d i a t o m i c, 4 m o l e s o f a r g o n a t t e m p e r a t u r e T m o n o a t o m i c a v e r a g e d e g r e e o f f r e e d o m f = \frac{2}{6} * 5 + \frac{4}{6} * 3 = \frac{5}{3} + 2 = \frac{11}{3} U = \frac{n f R T}{2} = \frac{6 (\frac{11}{3}) R T}{2} = 11 R T R e g a r d s$

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Q.184. A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature T. Neglecting all vibrational modes, the total internal energy of the system is (1) 4 RT (2) 15 RT (3) 9 RT (4) 11 RT

2 moles of oxygen diatomic , 4 moles of argon at temperature T monoatomicaverage degree of freedomf=26*5+46*3=53+2=113U=nfRT2=6113RT2=11RTRegards

Q.184. A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature T. Neglecting all vibrational modes, the total internal energy of the system is
(1) 4 RT
(2) 15 RT
(3) 9 RT
(4) 11 RT