Q.2. Sudhakar borrows Rs. 22500 at 10% per annum, compounded annually. If he repays Rs. 11250 at the end of first year and Rs. 12250 at the end of second year, find the amount of loan outstanding against him at the end of third year.

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$Let the a m o u n t o f l o a n o u t s \tan d i n g a g a i n s t h i m a t t h e e n d o f t h i r d y e a r = Rs x When Sudhakar borrows Rs 22500 at 10 % per annum compounded interest . then CI = P {(1 + \frac{R}{100})}^{n} (where P = principal, R = rate of interest, n = time) CI = 22500 {(1 + 0.1)}^{3} CI = 22500 {(1.1)}^{3} If he repays Rs 11250 at the end of first year, and Rs 12250 at the end of second year then, = 11250 (1.1) + 12250 {(1.1)}^{2} A . T . Q x + 11250 (1.1) + 12250 {(1.1)}^{2} = 22500 {(1.1)}^{3} \Rightarrow x + 12375 + 14822.5 = 29947.5 \Rightarrow x + 27197.5 = 29947.5 \Rightarrow x = 2750 So, the a m o u n t o f l o a n o u t s \tan d i n g a g a i n s t h i m a t t h e e n d o f t h i r d y e a r = Rs 2750$
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