Q.25. A body starts from rest and is found to cover 3 m during the 5th second of its motion. Find the acceleration if it is uniformly accelerated.
(Ans 0.67 $m / s^{2}$ )

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Solution

Distance travelled in nth second of uniformly accelerated motion is calculated by the expression :
$D_{n} = u + \frac{a}{2} (2 n - 1)$
Given, u = 0
n = 5 s
D₅ = 3 m
Substitute the given values in the above expression we get ,
a = 6 /9 = 0.67 m/s²
Regards

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Q.25. A body starts from rest and is found to cover 3 m during the 5th second of its motion. Find the acceleration if it is uniformly accelerated. (Ans 0.67 m/s2)

Distance travelled in nth second of uniformly accelerated motion is calculated by the expression : Dn = u + a2 2 n - 1 Given, u = 0 n = 5 s D5 = 3 m Substitute the given values in the above expression we get , a = 6 /9 = 0.67 m/s2 Regards

Q.25. A body starts from rest and is found to cover 3 m during the 5th second of its motion. Find the acceleration if it is uniformly accelerated.
(Ans 0.67 $m / s^{2}$ )

Distance travelled in nth second of uniformly accelerated motion is calculated by the expression :
$D_{n} = u + \frac{a}{2} (2 n - 1)$
Given, u = 0
n = 5 s
D₅ = 3 m
Substitute the given values in the above expression we get ,
a = 6 /9 = 0.67 m/s²
Regards