Question

Q.3State Raoult?s law. How is it formulated for solutions of volatile solutes?

Answer 1

Dear Student,
Raoult’s law states that in a solution, the vapour pressure of a component at a given temperature is equal to the mole fraction of that component in the solution multiplied by the vapour pressure of that component in the pure state.
​​​​​​For a volatile solute,
Let the vapour pressure of pure solvent be ${{\mathrm{p}}_{\mathrm{A}}}^0$
then the vapour pressure of solution containing volatile solute is given by :
${\mathrm{p}}_{\mathrm{A}}={{\mathrm{p}}_{\mathrm{A}}}^0\times {\mathrm{\chi }}_{\mathrm{A}}$
where${\mathrm{\chi }}_{\mathrm{A}}$ is the mole fraction of solvent.
Regards.
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