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Byju's Answer
Standard VI
Mathematics
Solving an Equation Using Transposition
Q 7. Simplify...
Question
Q 7. Simplify and solve the linear equation: 0.25 (4f – 3) = 0.05 (10f – 9)
Q 9. Solve for t:
3
t
-
2
3
+
2
t
+
3
2
=
t
+
7
6
Open in App
Solution
7
.
0
.
25
4
f
-
3
=
0
.
05
10
f
-
9
⇒
f
-
0
.
75
=
0
.
5
f
-
0
.
45
⇒
f
-
0
.
5
f
=
0
.
75
-
0
.
45
⇒
0
.
5
f
=
0
.
30
⇒
f
=
0
.
3
0
.
5
=
3
5
=
0
.
6
9
.
3
t
-
2
3
+
2
t
+
3
2
=
t
+
7
6
⇒
2
3
t
-
2
+
3
2
t
+
3
6
=
6
t
+
7
6
⇒
6
t
-
4
+
6
t
+
9
=
6
t
+
7
⇒
12
t
+
5
=
6
t
+
7
⇒
12
t
-
6
t
=
7
-
5
⇒
6
t
=
2
⇒
t
=
2
6
=
1
3
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0
Similar questions
Q.
Simplify and solve the following linear equation:
0.25
(
4
f
−
3
)
=
0.05
(
10
f
−
9
)
Q.
Solve the linear equation:
0.25
(
4
f
−
3
)
=
0.05
(
10
f
−
9
)
Q.
Solve for f:
0.25
(
4
f
−
3
)
=
0.05
(
10
f
−
9
)
Q.
Simplify and solve the following linear equation:
3
(
t
−
3
)
=
5
(
2
t
+
1
)
Q.
Question 10
0.25
(
4
f
−
3
)
=
0.05
(
10
f
−
9
)
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