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Question
Q. A 3-digit number 4a3 is added to another 3-digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then (a + b) is
Q. A 3-digit number 4a3 is added to another 3-digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then (a + b) is
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Solution
The correct option is D 8
4a3 + 984 = 13b7
a + 8 = b
And
(7 + 3) - (b + 1) = 9 – b is divisible by 11
9 – b = 0, b = 9 a = -1
a + b = 8
4a3 + 984 = 13b7
a + 8 = b
And
(7 + 3) - (b + 1) = 9 – b is divisible by 11
9 – b = 0, b = 9 a = -1
a + b = 8
Suggest Corrections
8
is a 3-digit number, then the number
is always divisible by