Q. A and B together can complete a work in 12 days. If A alone can complete that work in 30 days, then in how many days can B alone complete the same work?

21 days

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42 days

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30 days

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20 days

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Solution

The correct option is D 20 days
$12 \times 5 = 60 & 30 \times 2 = 60.$

$S o, B a l o n e = L C M o f 12 & 30 / (d i f f e r e n c e o f m u l t i p l i e r s)$

$= 60 / (5 - 2) = 60 / 3 = 20 d a y s .$

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Q. A and B together can complete a work in 12 days. If A alone can complete that work in 30 days, then in how many days can B alone complete the same work?

The correct option is D 20 days12×5=60 & 30×2=60. So,B alone=LCM of 12 & 30/(difference of multipliers) =60/(5–2)=60/3=20days.

The correct option is D 20 days
$12 \times 5 = 60 & 30 \times 2 = 60.$

$S o, B a l o n e = L C M o f 12 & 30 / (d i f f e r e n c e o f m u l t i p l i e r s)$

$= 60 / (5 - 2) = 60 / 3 = 20 d a y s .$