CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Q. A ball is dropped from a height of 81m. Each time it hits the ground, it bounces back up to two thirds of the distance it fell down. Find the total distance covered by the ball when it reaches the top position after the third bounce.

A
275
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
285
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
300
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
265
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 285
Initial drop = a = 81
Distance travelled each time after a bounce =23 of a, r = 23
Distance travelled by ball when it reaches top position of third bounce
=81+(2×23×81)+(2×(23)2×81)+(81×(23)3)=81+108+72+24=285

flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Probability
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon