Question

Q: A CAR STARTS FROM REST AND ACCELERATES UNIFORMLY OVER A TIME OF 5.28 SECONDS FOR A DISTANCE OF 110 m.
DETERMINE THE ACCELERATION OF THE CAR.

Answer 1

$$\begin{gathered} \mathrm{From}\mathrm{the}\mathrm{equations}\mathrm{of}\mathrm{motion}\mathrm{of}\mathrm{kinematics}, \\ \mathrm{s}=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2 \\ \mathrm{where} \\ \mathrm{u}=\mathrm{Initial}\mathrm{velocity} \\ \mathrm{t}=\mathrm{time} \\ \mathrm{a}=\mathrm{acceleration} \\ \mathrm{Substitute}\mathrm{u}=0: \\ \mathrm{s}=\frac{1}{2}{\mathrm{at}}^2 \\ \mathrm{a}=\frac{2\mathrm{s}}{{\mathrm{t}}^2} \\ =\frac{2\left(110\right)}{5.{28}^2} \\ \mathbf{}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{9}\mathbf{}\mathbf{m}\mathbf{/}{\mathbf{s}}^{\mathbf{2}} \end{gathered}$$