Q. A spring with spring constant k when compressed by 1 cm, the potential energy stored is U. if it is further compressed by 3 cm then change in potential energy is
3U
9U
8U
15U

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Solution

U = 0.5kx^2

U = 0.5k (1)^2
U = 0.5k

Final potential energy (U’) = 0.5 * k * (4)^2
= 16 * (0.5 k)
= 16U

Change in potential energy = 16U - U = 15U

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Q. A spring with spring constant k when compressed by 1 cm, the potential energy stored is U. if it is further compressed by 3 cm then change in potential energy is 3U 9U 8U 15U

U = 0.5kx^2 U = 0.5k (1)^2 U = 0.5k Final potential energy (U’) = 0.5 * k * (4)^2 = 16 * (0.5 k) = 16U Change in potential energy = 16U - U = 15U

Q. A spring with spring constant k when compressed by 1 cm, the potential energy stored is U. if it is further compressed by 3 cm then change in potential energy is
3U
9U
8U
15U

U = 0.5kx^2

U = 0.5k (1)^2
U = 0.5k

Final potential energy (U’) = 0.5 * k * (4)^2
= 16 * (0.5 k)
= 16U

Change in potential energy = 16U - U = 15U