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Question

Q. Arrange the following species in the increasing order of their Ionic radius ( with reasons ) :
C^4+, S^2-, Cl^1-,K^1+, Ca^2+, Al^3+, Mg^2+, O^2-,F^1-

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Solution

Some of the given species (ions) has the same number of electrons Hence, the given species are isoelectronic, i.e

O2- has 8+2= 10 electrons
F- has 9+1 = 10 electrons
Mg2+ has 12-2 = 10 electrons
Al3+ has 13-3= 10 electrons

Ca2+ has 20-2 = 18 electrons
K1+ has 19-1 = 18 electrons
Cl 1- has 17+1=18 electrons
S 2- has 16+2 = 18 electrons


C 4+ has 6-4 = 2 electrons

Among these C 4+ is smallest

Then comes ions having 10 electrons .
Their order is
The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge.
The arrangement of the given species in order of their increasing nuclear charge is as follows:
O2– < F– < Mg2+ < Al3+
Nuclear charge = +8, +9 ,+12 ,+13
Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows:
Al3+ < Mg2+ < F– < O2–

Then comes the ions with 18 number of electrons

Their order is

The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge.
The arrangement of the given species in order of their increasing nuclear charge is as follows:
S 2– < Cl– < K+ < Ca 2+
Nuclear charge = +10,+11, +13,+14
Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows:
Ca2+ < K+ < Cl - < S2–

So over all increasing order of ionic radii is

C4+<Al3+<Mg2+<F-<O2-<Ca2+<K+<Cl-<S2-<

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