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Question

[[Q]]

Calculate a) G°and b) the equilibrium constant for the formation of NO2 from NO and O2 at 298 K

where fG° (NO2) = 52.0 kJ/mol

fG° (NO) = 87.0 kJ/mol

fG° (O2) = 0 kJ/mol

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Solution

(a) For the given reaction,

G° = G°( Products) – G°( Reactants)

G° = 52.0 – {87.0 + 0}

= – 35.0 kJ mol–1

(b) We know that,

G° = RT log Kc

G° = 2.303 RT log Kc

Hence, the equilibrium constant for the given reaction


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