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Question

Q. Consider the following multiplication problem:

(PQ) x 3 = RQQ, where P, Q and R are different digits and R ≠ 0.

What is the value of (P + R) ÷ Q?


A
1
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B
2
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C
5
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D
Cannot be determined
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Solution

The correct option is C 5

Here Q×3=a no. which has ‘Q’ in its unit’s place, and this happens only for P=5 (as 5 x 3 = 15). Also, P×3+1 (1 is carryover from 15) = R5. This will happen only when P=8 (as 8 x 3 + 1 = 25). Hence, P=8,R=2 and Q=5. Now (8+2)÷5=10÷2=5.


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