Question

Q). Express the given angles in circular motion:
(i) $104°36\text{'}\text{'}$
(ii) $104°36\text{'}$

Answer 1

Dear Student


$$\begin{gathered} Given \\ \left(i\right){104}^0{36}^{\text{'}} \\ ={104}^0+{\left(\frac{36}{60}\right)}^0 \\ ={\left(\frac{523}{5}\right)}^0 \\ =\frac{\mathrm{\pi }}{180}\times \frac{523}{5}radian \\ =\frac{523\mathrm{\pi }}{900} \\ \left(ii\right) \\ {104}^0{36}^{\text{'}\text{'}} \\ ={104}^0+{\left(\frac{36}{3600}\right)}^0 \\ ={\left(\frac{10401}{100}\right)}^0 \\ =\frac{\mathrm{\pi }}{180}\times \frac{10401}{100} \\ =\frac{10401\pi }{18000} \end{gathered}$$
Regards