Question

Q. Find the unit’s digit in $\left({264}^{102}\right)+\left({264}^{103}\right)$

• A. 8
• B. 4
• C. 6
• D. 0.0
• E. None of these

Answer 1

The correct option is D 0.0

$4^2$gives 6
$4^{102}$ gives units place 6
$4^{103}$ gives $6\times 4$ = 4 in units place
So 6 + 4 =0