Question

Q. Given that 10${}^{0.52}$ = x, 1010${}^{0.35}$ and x${}^z$ = y${}^2$ then the value of z is close to:

• A. 1.32
• B. 1.23
• C. 1.35
• D. 1.37
• E. None of these

Answer 1

The correct option is C 1.35

$x^z=y^2{10}^{z0.52}={10}^{0.35\times 2}=0.52z=.70z=\frac{70}{52}z=\frac{35}{26}z=1.346=1.35$