Question

Q(h, k) is the foot of the perpendicular of P(3, 6) on the line x - 2y + 4 =0.

If the slope of PQ is m, find $m^2$.

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Answer 1

PQ is r to the given line.

Slope of x - 2 y + 4 = $\frac{1}{2}$

$\Rightarrow$ $\frac{1}{2}\times m=-1$

$\Rightarrow$ m = -2

$\Rightarrow$ $m^2=4$