Q: In a quadrilateral ABCD, angle A + angle C = 2*(angle B + angle D). if angle A = 140 degree and angle D = 60 degree, then angle B is?

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In a quadrilateral ABCD, $∠ A + ∠ C$ is 2 times $∠ B + ∠ D$ . If $∠ A = 140^{\circ} a n d ∠ D = 60^{\circ}, t h e n ∠ B =$

A B C D

∠

A = 60

^{o}

∠

B :

∠

C :

∠

D = 2 : 3 : 7

∠

D =

A B C D

∠ A = 60^{\circ}

∠ B : ∠ C : ∠ D = 2 : 3 : 7

∠ D

A B C D

∠ A = 90^{\circ}, ∠ B = 70^{\circ}

∠ C = 90^{\circ}

∠ D

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