Q. In an election of 3 candidates A, B and C, A gets 50% more votes than B. A also beats C by 45000 votes. If it is known that B gets 5 percentage point more votes than C, find the number of voters on the voting list (given 90% of the voters on the voting list voted and no votes were illegal).

180000

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200000

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225000

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250000

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Solution

The correct option is D 250000
Let the votes obtained by C be x%, then the votes obtained by B and A will be (x+5)% and (95-2x)% respectively.
We know that A got 50% more votes than B, which implies $\frac{3}{2}$ (x+5)=95-2x
Solving, we get x=25%
So, A got 45%, B got 30% and C got 25%. Also, A beat C by 45000 votes, which equals to 20% of the votes casted.
20% of votes = 45000 $\Rightarrow$ 100% of votes = $45000 \times 5$ = 225000
Voters on voting list = $\frac{225000}{90} \times 100 = 250000$

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