Q. In the series – 1, 1, 4, 8, 9, 27, 16, 64, 25, X – what is the value of X?

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125

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625

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Solution

The correct option is C 125
This is a series based on squares and cubes of 1, 2, 3, 4, 5.

$1^{2}, 1^{3}, 2^{2}, 2^{3}, 3^{2}, 3^{3}, 4^{2}, 4^{3}, 5^{2}, 5^{3} a n d 5^{3} i s 125$

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Similar questions

{lim}_{n \to \infty} \frac{1 + 1 + 4 + 8 + 9 + 27 + 16 + 64 + . . .}{(1 + 2 + 3 + 4 + 5 + . . .)^{2}} =

\frac{18^{3} + 7^{3} + 3 \cdot 18 \cdot 7 \cdot 25}{3^{6} + 6 \cdot 243 \cdot 2 + 15 \cdot 181 \cdot 4 + 20 \cdot 27 \cdot 8 + 15 \cdot 9 \cdot 16 + 6 \cdot 3 \cdot 32 + 64}

1 + 4 + 16 + 64 + . . . . . . 9

A = \int \frac{d x}{x^{2} + 6 x + 25}

B = \int \frac{d x}{x^{2} - 6 x - 27}

12 (A + B) = λ . {tan}^{- 1} (\frac{x + 3}{4}) + μ . ln ∣ ∣ ∣ \frac{x - 9}{x + 3} ∣ ∣ ∣ + C

(λ + μ)

\dots

3^{1 / 4} {.9}^{1 / 8} {.27}^{1 / 16} {.81}^{1 / 32} . . . . . . . . . .,

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