Question

Q). Netra bought a satin ribbon of some length. She wants to cut the ribbon in equal pieces of same length. If she cuts the ribbon of a particular length, she gets 7 equal pieces and a small piece 1 cm long is left. If she increases the length of each piece by 1 cm, she gets 6 equal pieces and a small piece of 2 cm is left. What is the original length of the satin ribbon she bought?

Answer 1

Dear student,

$$\begin{gathered} Letthelengthofeachequalpiecesbexcm \\ Accordingtoquestion, \\ Sincethetotallengthofribbonwillbeequal \\ \therefore 7x+1=6(x+1)+2 \\ \Rightarrow 7x+1=6x+6+2 \\ \Rightarrow 7x-6x=6+2-1 \\ \Rightarrow x=7 \\ Now,originallengthofribbon=7x+1=7\times 7+1=49+1=50cm \end{gathered}$$
Regards