Q. Out of a group of 8 boys and 4 girls, a committee of 4 students is to be selected. What is the probability of exactly 2 girls getting selected in the committee?

\frac{49}{144}

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\frac{112}{165}

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\frac{56}{165}

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\frac{1}{3}

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Solution

The correct option is C $\frac{56}{165}$
Here, the probability of selecting 2 girls and 2 boys will be:

$8 C 2 \times 4 C 2 / 12 C 4 = (8 \times 7 / 2) / (4 \times 3 / 2) / 12 \times 11 \times 10 \times 9 / 4 \times 3 \times 2 = 56 / 165$

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Q. Out of a group of 8 boys and 4 girls, a committee of 4 students is to be selected. What is the probability of exactly 2 girls getting selected in the committee?

The correct option is C 56165Here, the probability of selecting 2 girls and 2 boys will be: 8C2×4C2/12C4=(8×7/2)/(4×3/2)/12×11×10×9/4×3×2=56/165

The correct option is C $\frac{56}{165}$
Here, the probability of selecting 2 girls and 2 boys will be:

$8 C 2 \times 4 C 2 / 12 C 4 = (8 \times 7 / 2) / (4 \times 3 / 2) / 12 \times 11 \times 10 \times 9 / 4 \times 3 \times 2 = 56 / 165$