Q-p -q-p-A- p2-q2B- q2-p2C- p2-q2D- q-p2

The correct option is B Algebraic Identity : (q + p) × (q p) = q^2 p^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Expression Formation

q+p ×q-p=?A. ...

Question

$(q + p) \times (q - p) = ?$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

If tan A, tan B are the roots of $x^{2} - P x + Q = 0$ the value of $s i n^{2}$ (A+B)=(where P, Q $ϵ$ R)

t a n A, t a n B

x^{2} - p x + q = 0

s i n^{2} (A + B)

Given that tan A, tan B are the roots of the equation $x^{2}$ - px + q = 0, then the value of $s i n^{2}$ (A + B) is

p^{2} q^{2}

p^{2}

p, q a n d r

(p \neq q, r \neq 0)

\frac{1}{x + p} + \frac{1}{x + q} = \frac{1}{r}

Join BYJU'S Learning Program