Q. The 5th term in an AP is 27. The common difference is 4. Find the sum of 1st 15 terms

600

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585

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575

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590

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None of these

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Solution

The correct option is B 585
d = 4
a + 4d = 27
a = 11
15 $^{t h}$ term = a + 14d = 11 + 14 $\times$ 4 = 67
Sum of 1 $^{s t}$ 15 terms = $\frac{67 + 11}{2} \times 15$
= 585

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