Q- The ends of a stretched wire of length L are fixed at x - 0 and x - L- In one experiment the displacement of the wire is y1-Asin-xL-sin-t and energy is E1 and in other experiment its displacement is y2-Asin-2-xL-sin2-t and energy is E2 -Then-A E2-E1-B E2-2E1-C E2-4E1-D E2-16E1

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Standard XII

Physics

Intensity vs Photocurrent

Q. The ends o...

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Q. The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1=Asin(πxL)sinωt and energy is E1 and in other experiment its displacement is y2=Asin(2πxL)sin2ωt and energy is E2 .Then A E2=E1 B E2=2E1 C E2=4E1 D E2=16E1

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The ends of a stretched wire of length L are fixed at x=0 and x=L In one experiment, the displacement of the wire is $y_{1} = A s i n (\frac{π x}{L}) s i n ω t$ and energy is $E_{1}$ , and in another experiment its displacement is $y_{2} = A s i n (\frac{2 π x}{L}) s i n 2 ω t$ and energy is $E_{2}$ . Then

Q. The ends of a stretched wire of length

L

are fixed at

x = 0

and

x = L

. If in an experiment, the displacement of the wire is

y_{1} = A sin (\frac{π x}{L}) sin ω t

and energy is

E_{1}

and in another experiment, its displacement is

y_{2} = A sin (\frac{2 π x}{L}) sin 2 ω t

and energy is

E_{2}

, then
[Assume, there is no energy loss at the ends of the stretched wire]

The ends of a stretched wire of length $L$ are fixed at $x$ = 0 and $x$ = $L$ . In one experiment the displacement of the wire is $y_{1}$ = $A s i n (\frac{π x}{L}) s i n ω t$ and energy is $E_{1}$ and in another experiment its displacement is $y_{2}$ = $A s i n (\frac{2 π x}{L}) s i n 2 ω t$ and energy is $E_{2}$ . Then