Q. The equivalent mass of H3PO4 (Molecular weight = 98 g/mol) and Na2HPO4 (Molecular weight = 142 g/mol) in the reaction are respectively :- H3PO4 + 2NaOH → Na2HPO4 + 2H2O (1) 49, 142 (2) 49, 71 (3) 98, 71 (4) 98, 142

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H_{3} P O_{4}

N a H_{2} P O_{4}

N a_{2} H P O_{4}

N a_{3} P O_{4}

98

49

32.66

H_{3} P O_{4} + 2 N a O H \to N a_{2} H P O_{4}

H_{3} P O_{4}

2 N a O H + H_{3} P O_{4} \to N a_{2} H P O_{4} + 2 H_{2} O

H_{3} P O_{4}

N a H_{2} P O_{4}

2 N a O H + H_{3} P O_{4} \to {N a}_{2} H P O_{4} + 2 H_{2} O

100

H_{3} P O_{4} = 98

M g (O H)_{2} = 58.3

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