Question

Q.The standard reduction potential of Cu⁺/Cu electrode is 0.34 V . At what concentration of Cu²⁺ ions will the electrode potential be zero at 298 K ?

Answer 1

The solution is as follows:


$$\begin{gathered} E=E^0+\hspace{0.17em}\frac{RT}{nF}\log \frac{Cu}{C{u}^{2+}} \\ 0=0.34+\frac{8.314\times 298}{2\times 96500}\log \frac{Cu}{C{u}^{2+}} \\ \log \frac{Cu}{C{u}^{2+}}=26.3 \\ \left[Cu\right]=5.011\times {10}^{-27}\left[C{u}^{2+}\right] \\ WhenconcentrationofC{u}^{2+}is\approx {10}^{27}M,thenE=0V. \end{gathered}$$