Q. Two forces, $F_{1} a n d F_{2}$ are acting on a body. One force is double that of the other the resultant is equal to the greater force. Then the angle between the two forces is
a) $\cos^{- 1}$ (1/2)
b) $\cos^{- 1}$ (—1/2)
c) $\cos^{- 1}$ (—1/4)
d) $\cos^{- 1}$ (1/4)

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Solution

Dear Student,

$F_{1} = 2 F_{2} {F_{1}}^{2} = {F_{1}}^{2} + \frac{{F_{1}}^{2}}{2} + {F_{1}}^{2} \cos θ \cos θ = \frac{- 1}{2} θ = \cos^{-} (\frac{- 1}{2}) o p t i o n b R e g a r d s$

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Q. Two forces, $F_{1} a n d F_{2}$ are acting on a body. One force is double that of the other the resultant is equal to the greater force. Then the angle between the two forces is
a) $\cos^{- 1}$ (1/2)
b) $\cos^{- 1}$ (—1/2)
c) $\cos^{- 1}$ (—1/4)
d) $\cos^{- 1}$ (1/4)

Dear Student,

$F_{1} = 2 F_{2} {F_{1}}^{2} = {F_{1}}^{2} + \frac{{F_{1}}^{2}}{2} + {F_{1}}^{2} \cos θ \cos θ = \frac{- 1}{2} θ = \cos^{-} (\frac{- 1}{2}) o p t i o n b R e g a r d s$