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Young's Modulus of Elasticity

Q. Two spring...

Question

Q. Two springs have force constant K1 and K2 ( K1> K2). Each spring is extended by same force F. Ifthe elastic potential energy are E1 and E2 then E1/E2 is
K1/K2
K2/K1
✓(K1/K2)
✓(K2/K1)

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Solution

Expansion of 1st string
change in x= f/k1

expansion in 2nd string
change in x= f/k2

sso,
ΔE1/ΔE2= 1/2 k1(Δx1)² divided by 1/2 k2(Δx2)²
E1/E2= k2/k1

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