Q. What is the least number that must be added so that 3196 is divisible by 24, 50 and 105?

1004

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1006

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996

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1010

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None of these

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Solution

The correct option is A 1004
The LCM of 24, 50 and 105 is 4200
So 4200- 3196 = 1004 should be added to make it divisible

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