Q. Why sodium peroxide is used as an oxidising agent in inorganic chemistry , since sodium is a strong reducing agent ?

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Solution

Remember some points
Increase of O. N is oxidation
Decrease of O. N is reduction
The elements which is undergoing oxidation is reducing agent
The element which is undergoing reduction is oxidising agent
Now in Na2O2(sodium peroxide) O. N OF SODIUM is +1 and it cannot increase its oxidation no. to +2 +3…. . So it will decrease its oxidation state from +1 to zero.. Now look at point 2 and 4.. Decrease of oxidation state is reduction and element who undergoes reduction acts as an oxidising agent

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Question 10

Hydrogen peroxide is .......

(a) an oxidising agent

(b) a reducing agent

(d) neither oxidising nor reducing agent

Question 6

Consider the reactions

(i) $H_{2} O_{2} + 2 H I \to I_{2} + 2 H_{2} O$
(ii) $H O C l + H_{2} O_{2} \to H_{3} O^{+} C l^{-} + O_{2}$

Which of the following statements is correct about $H_{2} O_{2}$ with reference to these reactions? Hydrogen peroxide is ........

(a) an oxidising agent in both (i) and (ii)

(b) an oxidising agent in (i) and reducing agent in (ii)

(d) a reducing agent in both (i) and (ii)

H_{2} O_{2}

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