Question

Q1. Balance the following chemical equations:

$\mathrm{NaOH}+\mathrm{H}{}_2\mathrm{SO}{}_4\to \mathrm{Na}{}_2\mathrm{SO}{}_4+\mathrm{H}{}_2\mathrm{O}$

Answer 1

Balancing of chemical equation:

Step 1: Write unbalanced equation.

$\mathrm{NaOH}+\mathrm{H}{}_2\mathrm{SO}{}_4\to \mathrm{Na}{}_2\mathrm{SO}{}_4+\mathrm{H}{}_2\mathrm{O}$

Step 2: Write down the number of atoms of each element present on both reactant as well as product side.

Element Reactant side Product side

$\mathrm{Na}$ $1$ $2$

$\mathrm{O}$ $5$ $5$

$\mathrm{H}$ $3$ $2$

$\mathrm{S}$ $1$ $1$

Step 3: Add coefficients to balance the number of atoms at both the sides

Firstly balance Na at reactant side by adding $2$ before $\mathrm{NaOH}$

$2\mathrm{NaOH}+\mathrm{H}{}_2\mathrm{SO}{}_4\to \mathrm{Na}{}_2\mathrm{SO}{}_4+\mathrm{H}{}_2\mathrm{O}$

Secondly add $2$ before $\mathrm{H}{}_2\mathrm{O}$

$2\mathrm{NaOH}+\mathrm{H}{}_2\mathrm{SO}{}_4\to \mathrm{Na}{}_2\mathrm{SO}{}_4+2\mathrm{H}{}_2\mathrm{O}$

Balanced equation is:

$2\mathrm{NaOH}\left(\mathrm{aq}\right)+\mathrm{H}{}_2\mathrm{SO}{}_4(\mathrm{aq})\to \mathrm{Na}{}_2\mathrm{SO}{}_4(\mathrm{aq})+2\mathrm{H}{}_2\mathrm{O}\left(\mathrm{l}\right)$

Sodium hydroxide Sulphuric acid Sodium sulphate Water