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Q.2. An iceberg is floating in ocean. What fraction of its volume is above the water ?
(Given : density of ice = 900 kg/ $m^{3}$ and density of ocean water = 1030 kg / $m^{3}$ )
(A) 90 / 103
(B) 13 / 103
(C) 10 / 103
(D) 1 / 103

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Solution

Dear Student ,

$F r a c t i o n o f v o l u m e o f i c e a b o v e t h e w a t e r s u r f a c e i s g i v e n b y : 1 - \frac{v_{s}}{V_{0}} w h e r e v_{s} i s t h e v o l u m e o f o b j e c t i n w a t e r a n d V_{0} i s t h e v o l u m e o f t h e o b j e c t \frac{v_{s}}{V_{0}} = \frac{S_{0}}{S_{l}} w h e r e s_{0} i s t h e s p e c i f i c g r a v i t y o f o b j e c t a n d s_{l} i s t h e s p e c i f i c g r a v i t y o f l i q u i d s_{0} = \frac{d e n s i t y o f o b j e c t}{d e n s i t y o f w a t e r} s_{l} = \frac{d e n s i t y o f l q u i d}{d e n s i t y o f w a t e r} w h e n o b j e c t i s i c e a n d l i q u i d i s w a t e r s_{0} = 900 s_{l} = 1030 v o l u m e a b o v e t h e s u r f a c e = 1 - \frac{900}{1030} = \frac{130}{1030} = \frac{13}{103}$
Regards

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= 900 {kg/m}^{3}

= 1030 {kg/m}^{3}

= 900 {kg/m}^{3}

= 1030 {kg/m}^{3}

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50 \times 10^{- 11} {Pa}^{- 1}

10^{3} {kg/m}^{3}

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