Question

Q2. The hypotenuse of a right-angled triangle is 17 cm and the difference between other two sides is 7 cm. find the other two unknown sides.

• A. (a) 8, 15
• B. (b) 8, 7
• C. (c) 7, 15
• D. (d) 9, 15

Answer 1

The correct option is A

(a) 8, 15

let the shorter side be ‘x’ cm. Since, the difference between two sides is 7 cm, So, longer side would be (x+7)cm

As the right-angle has hypotenuse = 17 cm by using Pythagoras theorem, we get

$x^2+(x+7{)}^2=(17{)}^{2}or{x}^2+x^2+14x=49=289or{x}^2+7x-120=0$

x = -15 and x = 8, but ‘x’ cannot be negative. Therefore, one side = 8 cm and other side (8+7) = 15 cm.