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Question

Q24. Let there are three numbers which are in the ratio of 2:3:4 and the value of their LCM is 948 so what is the smallest of three numbers?


A

(a) 167

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B

(b) 168

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C

(c) 138

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D

(d) None of the above

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Solution

The correct option is D

(d) None of the above


Since we have the ratio of three numbers therefore the three numbers can be written in the form of 2x, 3x, 4x. We have the LCM of the three numbers i.e.948 and LCM of three numbers 2x,3x,4x = 12x where x is a multiple and 12x = 948; X = 79; Therefore the smallest number among three is 158, so d is the right answer.


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