wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

Q24. Let there are three numbers which are in the ratio of 2:3:4 and the value of their LCM is 948 so what is the smallest of three numbers?


A

(a) 167

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

(b) 168

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

(c) 138

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

(d) None of the above

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

(d) None of the above


Since we have the ratio of three numbers therefore the three numbers can be written in the form of 2x, 3x, 4x. We have the LCM of the three numbers i.e.948 and LCM of three numbers 2x,3x,4x = 12x where x is a multiple and 12x = 948; X = 79; Therefore the smallest number among three is 158, so d is the right answer.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Miscellaneous Concepts
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon