Question

Q38) A hiker walked for two days. On the second day the hiker walked 2 hours longer and at an average speed 1 km per hour faster than he walked on the first day. If during the two days he walked a total of 64 kms and spent a total of 18 hours walking, what was his average speed on the first day?

• A. (a) 2 kmph
• B. (b) 3 kmph
  
• C. (c) 4 kmph
• D. (d) 5 kmph

Answer 1

The correct option is B (b) 3 kmph


Ans:38)(b)
Sol: Let the avg. speed on first day = a;
No. of hours walked on firs day = x;
Then, no. of hours walked on second day = x+2;
Avg. speed on second day = a+1;
Given total time walked = 18 = x+(x+2)
x=8;
Given, Total distance = 64
x*a+((x+2)*(a+1)) =64
a=3;