Question

Q42. (a) How will you join three resistors of resistance 4 $\Omega$, 6 $\Omega$ and 12 $\Omega$ to get an equivalent resistance of 8$\Omega$.
(b) What would be the highest and the lowest equivalent resistance possible by joining these resistors.

Answer 1

Dear Student

$$\begin{gathered} Q42Whentheresistors6ohmand12ohmarejoinedinparallel \\ \frac{1}{Rp}=\frac{1}{6}+\frac{1}{12} \\ Rp=4ohmandwhenthisRpisjoinedwith4ohminseries \\ Rnet=4+4=8ohm \\ \left(b\right)Thelowestequivalentresis\tan ceiswhentheyarejoinedparallel \\ \frac{1}{Rp}=\frac{1}{4}+\frac{1}{6}+\frac{1}{12} \\ Rp=2ohm \\ Thehighestiswhentheyarejoinedinseries \\ Rs=4+6+12=22ohm \\ REGARDS \end{gathered}$$