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Byju's Answer
Standard VIII
Physics
Thrust & Pressure
Q6. Find the ...
Question
Q6. Find the value of x:
a) (125/ 8) X (125/ 8)
x
= (5/2)
18
b) 3
2x + 1
/ 9 = 27
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Solution
1)
125/8 × (125/8)^x = (5/2)^18
(5/2)³×[(5/2)^3]^x = (5/2)^18
(a^m)^n = a^mn
(5/2)^3 × (5/2)^3x = (5/2)^18
a^m × a^n = a^m+n
=> (5/2)^3+3x = (5/2)^18
=> as bases are equal exponents are equal
=> 3+3x = 18
=> 3x = 15 => x = 15/3 = 5
2)
3^(2x+1) /9=27
3^(2x+1)=27×9
3^(2x+1)=243
(3)^2x+1=(3).^5
3 will cancel out
So,
2x+1=5
2x=5-1
2x=4
x=4/2
x=2
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