QR/QS=QT/PR and angle 1is equal to angle 2. Show that triangle PQS ~ to triangle RTS

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\frac{Q R}{Q S} = \frac{Q T}{P R}

∠ 1 = ∠ 2

△ P Q S \sim △ T Q R

In fig, $\frac{Q T}{P R} = \frac{Q R}{Q S}$ and $∠ 1 = ∠ 2$ . Prove that $△ P Q S \sim △ T Q R$ .

\frac{Q T}{P R} = \frac{Q R}{Q S}

∠ 1 = ∠ 2

△ P Q S \sim △ T Q R

\frac{Q R}{Q S} = \frac{Q T}{P R} a n d

∠ 1 = ∠ 2

S h o w t h a t Δ P Q S \sim Δ T Q R

\frac{Q R}{Q S} = \frac{Q T}{P R} a n d ∠ 1 = ∠ 2.

Δ P Q S

\sim

Δ T Q R

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