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Byju's Answer
Standard XII
Mathematics
Intersection
PA-B=PA-PA⋂ B...
Question
P
(
A
−
B
)
=
P
(
A
)
−
P
(
A
⋂
B
)
=
P
(
A
⋃
B
)
−
P
(
B
)
=
P
(
A
⋂
¯
B
)
=
1
−
P
(
¯
A
⋂
B
)
A
True
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B
False
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Solution
The correct option is
A
True
P(A-B) is shown blue shaded region
P
(
A
)
−
P
(
A
⋂
B
) is again shown in the blue region
P
(
A
⋃
B
)
−
P
(
B
)=P(A)+P(B)-
P
(
A
⋂
B
)-P(B)
=
P
(
A
)
−
P
(
A
⋂
B
)
P
(
A
⋂
B
¯
)=
P
(
A
⋃
B
)
−
P
(
B
)
Also
P
(
A
∩
_
B
)
+
P
(
_
A
∩
B
)
=
1
⇒
P
(
A
∩
_
B
)
=
1
−
P
(
_
A
∩
B
)
Suggest Corrections
0
Similar questions
Q.
Consider the following statements:
(1)
P
(
¯
A
∪
B
)
=
P
(
¯
A
)
+
P
(
B
)
−
P
(
¯
A
∩
B
)
(2)
P
(
A
∩
¯
B
)
=
P
(
¯
B
)
−
P
(
A
∩
B
)
(3)
P
(
A
∩
B
)
=
P
(
B
)
P
(
A
|
B
)
Which of the above statements are correct?
Q.
If
P
(
A
)
=
0.7
and
P
(
A
∩
B
)
= 0.5 find
1.
P
(
A
−
¯
B
)
2.
P
(
¯
A
∪
B
)
Q.
If two events A and B are such that P(A) > 0 and
P
(
B
)
≠
1
, then
P
(
¯
A
¯
B
)
is equal to
Q.
If
A
and
B
be two events associated with a random experiment such that
P
(
A
)
=
0.3
,
P
(
B
)
=
0.4
and
P
(
A
∪
B
)
=
0.6
, then value of
P
(
¯
A
B
)
+
P
(
A
¯
B
)
is
Q.
Assertion :If
B
⊂
A
, then
P
(
A
∩
¯
B
)
=
P
(
A
)
−
P
(
B
)
. Reason:
(
A
∩
¯
B
)
∪
B
=
A
.
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