Question

Quadratic polynomial: $y=x^2-4x+4$, draw a graph and represent the zeroes of the polynomial.

Answer 1

Given quadratic polynomial is $y=x^2-4x+4$

To find the points on the graph, we will substitute few values of $x$ and find the values of $y$.

If $x=0$, then $y=0^2-4\times 0+4=0-0+4=4$

If $x=1$, then $y=1^2-4\times 1+4=1-4+4=1$

If $x=2$, then $y=2^2-4\times 2+4=4-8+4=0$

So, the points are $(0,4),(1,1),(2,0)$.
Plotting $(0,4),(1,1),(2,0)$ and joining them.
Here, the graph cuts $x$-axis at one distinct point $\text{A}$.
The $x$-coordinates of $\text{A}(2,0)$ is the one zeroes of the quadratic polynomial $y=x^2-4x+4$