Question

Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, $\angle DXA=\angle AYB$

If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

$AB=BC$ (ABCD is a square)

$\frac{1}{2}AB=\frac{1}{2}BC$

$AX=BY$ ($X$ and $Y$ are mid points of AB and BC respectively)

In $△AXD$ and $△ABY$,

$\angle DAX=\angle ABY$ (Each ${90}^{\circ }$)

$AX=BY$ (Proved above)

$AD=AB$ (ABCD is a square)

Thus, $△AXD\cong △BYA$

Hence, $\angle DXA=\angle AYB$ (By cpct)