Quadrilateral $M O R E$
$M O = 6 c m$
$O R = 4.5 c m$
$∠ M = 60^{o}$
$∠ O = 105^{o}$
$∠ R = 105^{o}$

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Solution

Let the Quadrilateral $M O R E$

In which $∠ M = 60^{\circ}, ∠ O = 105^{\circ}, ∠ R = 105^{\circ}$

By using angle sum property,

That the sum of interior angles of a quadrilateral is $= 360^{\circ}$

$∠ M + ∠ O + ∠ R + ∠ E = 360^{\circ}$

$60^{\circ} + 105^{\circ} + 105^{\circ} + ∠ E = 360^{\circ}$

$270^{\circ} + ∠ E = 360^{\circ}$

$∠ E = 360^{\circ} - 270^{\circ}$

$∠ E = 90^{\circ}$

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Similar questions

M O R E

M O = 6 c m, O R = 4.5 c m, ∠ M = 60^{o}, ∠ O = 105^{o}

∠ R = 105^{o}

M O R E

M O = 6 c m

O R = 4.5 c m

∠ M = 60^{o}

∠ O = 105^{o}

∠ R = 105^{o}

□ M O R E

Construct the Quadrilateral $M O R E$ where
Given $M O = 6 c m$ , $O R = 4.5 c m$ , $∠ M = 60^{\circ}, ∠ O = 105^{\circ} ∠ R = 105^{\circ}$

ℓ (M O) = 5.8 c m, ℓ (O R) = 4.4 c m, m ∠ M = 58^{o}, m ∠ O = 105^{o}, m ∠ R = 90^{o}

Question 1
Construct the Quadrilateral MORE where
Given MO=6cm, OR = 4.5 cm, $∠ M = 60^{\circ}, ∠ O = 105^{\circ} ∠ R = 105^{\circ}$

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