Question

Quality factor of the given circuit is

• A. 2
• B. 1
• C. 0.8
• D. 0.4

Answer 1

The correct option is D 0.4

$Q=2\pi \frac{\frac{1}{2}L{i}_0^2}{\frac{1}{2}{i}_0^{2}RT}=\frac{2\pi L}{RT}=\frac{L\omega }{R}Q=\frac{2\times {10}^{-3}\times {10}^3}{5}=\frac{2}{5}=0.4$